Find the roots of the following quadratic equ | vedclass

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Question

(C) Given equation is $21 x^{2}-2 x+\frac{1}{21}=0$.To simplify,multiply the entire equation by $21$ on both sides:$21(21 x^{2}-2 x+\frac{1}{21}) = 21

Vedclass · Accepted Answer

$\frac{1}{21}, \frac{1}{21}$

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(C) Given equation is $21 x^{2}-2 x+\frac{1}{21}=0$.To simplify,multiply the entire equation by $21$ on both sides:$21(21 x^{2}-2 x+\frac{1}{21}) = 21(0)$$441 x^{2}-42 x+1=0$Now,factorise the quadratic equation by splitting the middle term:$441 x^{2}-21 x-21 x+1=0$Group the terms:$(441 x^{2}-21 x)-(21 x-1)=0$$21 x(21 x-1)-1(21 x-1)=0$Factor out $(21 x-1)$:$(21 x-1)(21 x-1)=0$Setting each factor to zero:$21 x-1=0 \Rightarrow x=\frac{1}{21}$$21 x-1=0 \Rightarrow x=\frac{1}{21}$Thus,the roots of the equation are $\frac{1}{21}$ and $\frac{1}{21}$.

Find the roots of the following quadratic equation by the factorisation method:
$21 x^{2}-2 x+\frac{1}{21}=0$

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Find the roots of the following quadratic equation by the factorisation method:$21 x^{2}-2 x+\frac{1}{21}=0$