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(A) Given equation is $5x^{2} + 13x + 8 = 0$.On comparing with the standard form $ax^{2} + bx + c = 0$,we get:$a = 5, b = 13, c = 8$.The quadratic for

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$-1, -\frac{8}{5}$

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(A) Given equation is $5x^{2} + 13x + 8 = 0$.On comparing with the standard form $ax^{2} + bx + c = 0$,we get:$a = 5, b = 13, c = 8$.The quadratic formula is given by $x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$.Substituting the values:$x = \frac{-(13) \pm \sqrt{(13)^{2} - 4(5)(8)}}{2(5)}$$x = \frac{-13 \pm \sqrt{169 - 160}}{10}$$x = \frac{-13 \pm \sqrt{9}}{10}$$x = \frac{-13 \pm 3}{10}$.Case $1$: $x = \frac{-13 + 3}{10} = \frac{-10}{10} = -1$.Case $2$: $x = \frac{-13 - 3}{10} = \frac{-16}{10} = -\frac{8}{5}$.Thus,the roots are $-1$ and $-\frac{8}{5}$.

Find the roots of the quadratic equation by using the quadratic formula:
$5x^{2} + 13x + 8 = 0$

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Find the roots of the quadratic equation by using the quadratic formula:$5x^{2} + 13x + 8 = 0$