Find the sum of the first 30 terms of the A.P | vedclass

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(C) The given $A.P.$ is $15, 20, 25, \ldots$Here,the first term $a = 15$ and the common difference $d = 20 - 15 = 5$.The number of terms $n = 30$.The

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$2625$

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(C) The given $A.P.$ is $15, 20, 25, \ldots$Here,the first term $a = 15$ and the common difference $d = 20 - 15 = 5$.The number of terms $n = 30$.The sum of the first $n$ terms of an $A.P.$ is given by the formula $S_n = \frac{n}{2} [2a + (n - 1)d]$.Substituting the values: $S_{30} = \frac{30}{2} [2(15) + (30 - 1)5]$.$S_{30} = 15 [30 + (29 	imes 5)]$.$S_{30} = 15 [30 + 145]$.$S_{30} = 15 	imes 175$.$S_{30} = 2625$.

Find the sum of the first $30$ terms of the $A.P.$ $15, 20, 25, \ldots$

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