Find the value of sqrt{6492304}. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To find the square root of $6492304$,we can use the long division method:$1$. Group the digits in pairs from right to left: $6, 49, 23, 04$.$2$. F

Vedclass · Accepted Answer

$2548$

Vedclass · Answer

(C) To find the square root of $6492304$,we can use the long division method:$1$. Group the digits in pairs from right to left: $6, 49, 23, 04$.$2$. Find the largest square less than or equal to $6$,which is $2^2 = 4$. Subtract $4$ from $6$ to get $2$. Bring down $49$,making it $249$.$3$. Double the divisor $(2 	imes 2 = 4)$. Find a digit $x$ such that $4x 	imes x \leq 249$. For $x = 5$,$45 	imes 5 = 225$. Subtract $225$ from $249$ to get $24$. Bring down $23$,making it $2423$.$4$. Double the current divisor $(25 	imes 2 = 50)$. Find a digit $y$ such that $50y 	imes y \leq 2423$. For $y = 4$,$504 	imes 4 = 2016$. Subtract $2016$ from $2423$ to get $407$. Bring down $04$,making it $40704$.$5$. Double the current divisor $(254 	imes 2 = 508)$. Find a digit $z$ such that $508z 	imes z = 40704$. For $z = 8$,$5088 	imes 8 = 40704$.Therefore,$\sqrt{6492304} = 2548$.

Find the value of $\sqrt{6492304}$.

Similar Questions

For what value of $x$ is the statement $\left(\frac{x}{15}\right)\left(\frac{x}{135}\right)=1$ true?

If $\frac{5+2 \sqrt{3}}{7+4 \sqrt{3}}=a+b \sqrt{3},$ then

$\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}$ is equal to

The $H.C.F.$ and $L.C.M.$ of two numbers are $21$ and $84$ respectively. If the ratio of the two numbers is $1:4$,then the larger of the two numbers is

If $x=\frac{\sqrt{3}+1}{\sqrt{3}-1}$ and $y=\frac{\sqrt{3}-1}{\sqrt{3}+1},$ then the value of $(x^{2}+y^{2})$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module