Find the value of $x$ and $y$ in the following nuclear reaction:
${}_{92}^{235} U + {}_{0}^{1} n \rightarrow {}_{x}^{133} Sb + {}_{41}^{y} Nb + 4 {}_{0}^{1} n$

  • A
    $(51, 95)$
  • B
    $(51, 99)$
  • C
    $(92, 1)$
  • D
    $(133, 41)$

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