Five current-carrying conductors meet at a po | vedclass

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(B) According to Kirchhoff's Current Law $(KCL)$,which is based on the law of conservation of charge,the algebraic sum of currents meeting at any junc

Vedclass · Accepted Answer

$1$ $A$ from $P$ to $Q$

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(B) According to Kirchhoff's Current Law $(KCL)$,which is based on the law of conservation of charge,the algebraic sum of currents meeting at any junction is zero.Mathematically,$\sum I = 0$.Taking currents entering the junction as positive and currents leaving the junction as negative:Incoming currents: $5$ $A$ and $4$ $A$.Outgoing currents: $3$ $A$,$5$ $A$,and the unknown current $I_Q$ (assuming it leaves the junction $P$ towards $Q$).Applying the junction rule at point $P$:$(+5) + (+4) + (-3) + (-5) - I_Q = 0$$9 - 8 - I_Q = 0$$1 - I_Q = 0$$I_Q = 1$ $A$.Since the result is positive,our assumption that the current leaves the junction $P$ towards $Q$ is correct.Therefore,the current is $1$ $A$ flowing from $P$ to $Q$.

Five current-carrying conductors meet at a point $P$. Based on the provided image,what is the magnitude and direction of the current in the fifth conductor connected to point $Q$?

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