Five identical resistors, each of resistance | vedclass

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(D) Given: $R = 1500 \Omega$, $V = 300 	ext{ V}$.Looking at the circuit diagram, the five resistors are connected in parallel across the battery. How

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$0.6$

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(D) Given: $R = 1500 \Omega$, $V = 300 	ext{ V}$.Looking at the circuit diagram, the five resistors are connected in parallel across the battery. However, the ammeter $A$ is placed in series with the last three resistors.Let the resistors be $R_1, R_2, R_3, R_4, R_5$ from left to right.Resistors $R_1$ and $R_2$ are connected directly across the $300 	ext{ V}$ battery.Resistors $R_3, R_4,$ and $R_5$ are connected in parallel with each other, and this combination is in series with the ammeter $A$ across the $300 	ext{ V}$ battery.The equivalent resistance of the three resistors $R_3, R_4, R_5$ in parallel is $R_{eq} = R / 3 = 1500 / 3 = 500 \Omega$.The current $I$ flowing through the ammeter $A$ is the current through this parallel combination:$I = \frac{V}{R_{eq}} = \frac{300}{500} = \frac{3}{5} 	ext{ A} = 0.6 	ext{ A}$.

Five identical resistors, each of resistance $R = 1500 \Omega$, are connected to a $300 \text{ V}$ battery as shown in the circuit. The reading of the ideal ammeter $A$ is: (in $\text{ A}$)

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