Flocculation value of BaCl_2 is much less tha | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to the Hardy-Schulze rule,the coagulating power of an ion is directly proportional to its valence.For sol $A$,the flocculation value of

Vedclass · Accepted Answer

Sol $A$ is negatively charged and sol $B$ is positively charged.

Vedclass · Answer

(D) According to the Hardy-Schulze rule,the coagulating power of an ion is directly proportional to its valence.For sol $A$,the flocculation value of $BaCl_2$ $(Ba^{2+})$ is less than $KCl$ $(K^+)$,which implies that the cation $Ba^{2+}$ is more effective at coagulation than $K^+$. Therefore,sol $A$ must be negatively charged.For sol $B$,the flocculation value of $Na_2SO_4$ $(SO_4^{2-})$ is less than $NaBr$ $(Br^-)$,which implies that the anion $SO_4^{2-}$ is more effective at coagulation than $Br^-$. Therefore,sol $B$ must be positively charged.Thus,sol $A$ is negatively charged and sol $B$ is positively charged.

Flocculation value of $BaCl_2$ is much less than that of $KCl$ for sol $A$ and flocculation value of $Na_2SO_4$ is much less than that of $NaBr$ for sol $B.$ The correct statement among the following is

Similar Questions

Movement of colloidal particles under the influence of an electrostatic field is called:

Gold sol is not a

In which of the following is the Tyndall effect $NOT$ observed?

What causes Brownian motion in colloidal dispersion?

The correct option among the following is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module