Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that $BF_3$ has no dipole moment but $PF_3$ does?
- A$BF_3$ is not spherically symmetrical but $PF_3$ is
- B$BF_3$ molecule must be linear
- CThe atomic radius of $P$ is larger than the atomic radius of $B$
- DThe $BF_3$ molecule must be planar triangular
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