Fluorine reacts with dilute NaOH to form a ga | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of fluorine with dilute $NaOH$ is given by: $2F_2 + 2NaOH \rightarrow 2NaF + OF_2 + H_2O$ Thus, the gaseous product $A$ is oxygen dif

Vedclass · Accepted Answer

$103^{\circ}$

Vedclass · Answer

(B) The reaction of fluorine with dilute $NaOH$ is given by: $2F_2 + 2NaOH \rightarrow 2NaF + OF_2 + H_2O$ Thus, the gaseous product $A$ is oxygen difluoride $(OF_2)$. In $OF_2$, the central oxygen atom is $sp^3$ hybridized. It has two bond pairs and two lone pairs of electrons. Due to the strong repulsion between the two lone pairs of electrons on the oxygen atom, the bond angle is compressed from the ideal tetrahedral angle of $109^{\circ} 28^{\prime}$ to $103^{\circ}$.

Fluorine reacts with dilute $NaOH$ to form a gaseous product $A$. The bond angle in the molecule of $A$ is

Similar Questions

Aluminium trifluoride is insoluble in anhydrous $HF$ but dissolves on addition of $NaF$. Aluminium trifluoride precipitates out of the resulting solution when gaseous $BF_3$ is bubbled through. Give reasons.

Which one of the following arrangements does not give the correct picture of the trends indicated against it?

The bond dissociation energy is highest for

Anhydrous ferric chloride is prepared by

Which of the following can not undergo hydrolysis?

Vedclass Test Series

Exam Paper Generator

Online Exam Module