The electronic configurations of $4$ atoms are given below:
$P = [Ne] \, 3s^2 3p^3$
$Q = [Ar] \, 3d^{10} 4s^2 4p^3$
$R = [He] \, 2s^2 2p^5$
$S = [Ne] \, 3s^1$
Which of the following statements is incorrect?

  • A
    $EA : Q > R$ (where $EA = \text{electron affinity}$)
  • B
    $EN : R > P$ (where $EN = \text{electronegativity}$)
  • C
    $IP : P > S$ (where $IP = \text{ionisation potential}$)
  • D
    Size : $S > R$

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$(c)$ Order of electronegativity $sp > sp^2 > sp^3$
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Match the following elements,given as hints to their first,second ionization enthalpies and electron gain enthalpies.
List-$I$List-$II$
$i)$ Most reactive non-metal$A$. $\Delta H_1=419, \Delta H_2=3051, \Delta_{Eg} H=-48$
$ii)$ Most reactive metal$B$. $\Delta H_1=1681, \Delta H_2=3374, \Delta_{Eg} H=-328$
$iii)$ Least reactive element$C$. $\Delta H_1=738, \Delta H_2=1451, \Delta_{Eg} H=-40$
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