The following is a confirmatory test for arom | vedclass

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(D) The reaction shown is the diazotization of aniline followed by a coupling reaction to form an azo dye. Step $1$: Aniline reacts with $NaNO_2 + HCl

Vedclass · Accepted Answer

$A = NaNO_2 + HCl, 0-5^{\circ}C$; $B = \beta	ext{-Naphthol}$

Vedclass · Answer

(D) The reaction shown is the diazotization of aniline followed by a coupling reaction to form an azo dye. Step $1$: Aniline reacts with $NaNO_2 + HCl$ at $0-5^{\circ}C$ to form benzenediazonium chloride. Thus,reagent $(A)$ is $NaNO_2 + HCl$ at $0-5^{\circ}C$. Step $2$: Benzenediazonium chloride reacts with $\beta	ext{-naphthol}$ in the presence of $NaOH$ to form a scarlet red dye (an azo dye). Thus,reagent $(B)$ is $\beta	ext{-naphthol}$. Therefore,the correct option is $(D)$.

List $I$ (Amines)	List $II$ $(pK_{b})$
$A$. Aniline	$I$. $3.25$
$B$. Ethanamine	$II$. $3.00$
$C$. $N$-Ethylethanamine	$III$. $9.38$
$D$. $N,N$-Diethylethanamine	$IV$. $3.29$

The following is a confirmatory test for aromatic primary amines. Identify reagent $(A)$ and $(B)$.

Similar Questions

Methyl isocyanide on hydrolysis gives

Match List $I$ with List $II$:
List $I$ (Amines) List $II$ $(pK_{b})$
$A$. Aniline $I$. $3.25$
$B$. Ethanamine $II$. $3.00$
$C$. $N$-Ethylethanamine $III$. $9.38$
$D$. $N,N$-Diethylethanamine $IV$. $3.29$

Choose the correct answer from the options given below:

Select the compound which on treatment with nitrous acid liberates nitrogen.

Consider the following reaction sequence and identify the correct option:

Which one of the following compounds gives carboxylic acid with $HNO_2$?

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