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(C) The given equation is $I = A T^2 e^{qV / V_L}$.Comparing this with the standard Richardson-Dushman equation for thermionic emission,$I = A T^2 e^{

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$\frac{kT}{V}$

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(C) The given equation is $I = A T^2 e^{qV / V_L}$.Comparing this with the standard Richardson-Dushman equation for thermionic emission,$I = A T^2 e^{-qV / kT}$ (where the exponent term represents the ratio of energy to thermal energy).In the given expression,the exponent is $\frac{qV}{V_L}$.Comparing the exponents: $\frac{qV}{V_L} = \frac{qV}{kT}$.Therefore,$V_L = \frac{kT}{V}$.

The relation between current and charge is given by $I = A T^2 e^{qV / V_L}$. What is the value of $V_L$?

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