Easy
For $ns$ orbital,the magnetic quantum number has value
- A$2$
- B$4$
- C$-1$
- D$0$
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Similar Questions
The total number of electrons present in all the $s$-orbitals,all the $p$-orbitals,and all the $d$-orbitals of the cesium ion $(Cs^+)$ are respectively:
Medium
View SolutionFor which of the following sets of four quantum numbers,an electron will have the highest energy?
$n$ $l$ $m$ $s$
$n$ $l$ $m$ $s$
Consider the following sets of quantum numbers:
$Set$ $(n)-(l)-(m)-(s)$ $(i)$ $(3)-(2)-(1)-(+1/2)$ $(ii)$ $(2)-(2)-(1)-(+1/2)$ $(iii)$ $(4)-(3)-(-2)-(-1/2)$ $(iv)$ $(1)-(0)-(-1)-(-1/2)$ $(v)$ $(3)-(2)-(3)-(+1/2)$
Which of the following sets of quantum numbers is not possible?
| $Set$ | $(n)-(l)-(m)-(s)$ |
| $(i)$ | $(3)-(2)-(1)-(+1/2)$ |
| $(ii)$ | $(2)-(2)-(1)-(+1/2)$ |
| $(iii)$ | $(4)-(3)-(-2)-(-1/2)$ |
| $(iv)$ | $(1)-(0)-(-1)-(-1/2)$ |
| $(v)$ | $(3)-(2)-(3)-(+1/2)$ |
Which of the following sets of quantum numbers is not possible?
MediumAIPMT 2007
View SolutionElectronic configuration of $C$ is
Easy
View SolutionKrypton $(_{36}Kr)$ has the electronic configuration $[Ar] 4s^2 3d^{10} 4p^6$. The $37^{th}$ electron will go into which of the following subshells?
Easy
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