For As_2S_3 sol, the most effective coagulati | vedclass

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Question

(C) According to the $Hardy-Schulze$ rule, the coagulating power of an ion is directly proportional to the magnitude of the charge on the ion.$As_2S_3

Vedclass · Accepted Answer

$FeCl_3$

Vedclass · Answer

(C) According to the $Hardy-Schulze$ rule, the coagulating power of an ion is directly proportional to the magnitude of the charge on the ion.$As_2S_3$ sol is a negatively charged colloid.To coagulate a negatively charged sol, a positively charged ion is required.The coagulating power of cations follows the order: $Al^{3+} > Ba^{2+} > Na^+$.Among the given options, $FeCl_3$ provides $Fe^{3+}$ ions, which have the highest positive charge $(+3)$ compared to $Ca^{2+}$ $(+2)$ and $Na^+$ $(+1)$.Therefore, $FeCl_3$ is the most effective coagulating agent.

List-$I$ (Sol)	List-$II$ (Method of preparation)
$A$. $As_2S_3$	$IV$. Double decomposition
$B$. $Au$	$I$. Bredig's arc method
$C$. $S$	$II$. Oxidation
$D$. $Fe(OH)_3$	$III$. Hydrolysis

For $As_2S_3$ sol, the most effective coagulating agent is

Similar Questions

Match the following:
List-$I$ (Sol) List-$II$ (Method of preparation)
$A$. $As_2S_3$ $IV$. Double decomposition
$B$. $Au$ $I$. Bredig's arc method
$C$. $S$ $II$. Oxidation
$D$. $Fe(OH)_3$ $III$. Hydrolysis
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