For s-orbitals,since psi (orbital) is indepen | vedclass

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(C) For $s-$orbitals,the wave function $\psi$ depends only on the distance $r$ from the nucleus and is independent of the angular coordinates $(	heta

Vedclass · Accepted Answer

both $(a)$ and $(b)$ are correct

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(C) For $s-$orbitals,the wave function $\psi$ depends only on the distance $r$ from the nucleus and is independent of the angular coordinates $(	heta, \phi)$.Since the probability density is given by $\psi^2$,if $\psi$ is independent of angles,then $\psi^2$ is also independent of angles.An orbital that is independent of angles is spherically symmetric,meaning the electron density is the same in all directions at a given distance $r$ from the nucleus.Therefore,both statements $(a)$ and $(b)$ are correct.

For $s-$orbitals,since $\psi$ (orbital) is independent of angles,the probability $(\psi^2)$ is

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