For a CE amplifier,current gain is 69. If the | vedclass

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(B) In a common emitter $(CE)$ configuration,the current gain $\beta$ is defined as the ratio of collector current $(I_C)$ to base current $(I_B)$: $\

Vedclass · Accepted Answer

$0.1\, mA, 6.9\, mA$

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(B) In a common emitter $(CE)$ configuration,the current gain $\beta$ is defined as the ratio of collector current $(I_C)$ to base current $(I_B)$: $\beta = \frac{I_C}{I_B}$.Given $\beta = 69$,we have $I_C = 69 I_B$.We know that the emitter current $(I_E)$ is the sum of the base current and collector current: $I_E = I_B + I_C$.Substituting the value of $I_C$,we get $I_E = I_B + 69 I_B = 70 I_B$.Given $I_E = 7\, mA$,we can solve for $I_B$: $7\, mA = 70 I_B \implies I_B = 0.1\, mA$.Now,calculate the collector current: $I_C = I_E - I_B = 7\, mA - 0.1\, mA = 6.9\, mA$.Thus,the base current is $0.1\, mA$ and the collector current is $6.9\, mA$.

For a $CE$ amplifier,current gain is $69$. If the emitter current is $7\, mA$,then the base current and collector current will be:

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