For a cell, the graph between the potential d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The terminal potential difference $V$ of a cell is given by the relation $V = E - Ir$, where $E$ is the $e.m.f.$ and $r$ is the internal resistanc

Vedclass · Accepted Answer

$2\,V$, $0.4\,\Omega$

Vedclass · Answer

(B) The terminal potential difference $V$ of a cell is given by the relation $V = E - Ir$, where $E$ is the $e.m.f.$ and $r$ is the internal resistance.Comparing this with the equation of a straight line $y = mx + c$, we get $V = -rI + E$.From the graph, when current $I = 0$, the potential difference $V = 2\,V$. This intercept on the $V$-axis represents the $e.m.f.$ of the cell, so $E = 2\,V$.The slope of the $V-I$ graph is equal to $-r$. The magnitude of the slope is $\frac{	ext{change in } V}{	ext{change in } I} = \frac{2 - 0}{5 - 0} = \frac{2}{5} = 0.4\,\Omega$.Therefore, the internal resistance $r = 0.4\,\Omega$.Thus, the $e.m.f.$ is $2\,V$ and the internal resistance is $0.4\,\Omega$.

For a cell, the graph between the potential difference $(V)$ across the terminals of the cell and the current $(I)$ drawn from the cell is shown in the figure. The $e.m.f.$ and the internal resistance of the cell are

Similar Questions

$A$ voltmeter of very high resistance is connected in the circuit as shown in the figure. The voltage shown by this voltmeter will be . . . . . . . (in $V$)

In the given circuit,the internal resistance of the $18\,V$ cell is negligible. If $R_1 = 400\,\Omega$,$R_3 = 100\,\Omega$,and $R_4 = 500\,\Omega$,and the reading of an ideal voltmeter across $R_4$ is $5\,V$,then the value of $R_2$ will be ........... $\Omega$.

In the circuit given, $E = 6.0 \, V$, $R_1 = 100 \, \Omega$, $R_2 = R_3 = 50 \, \Omega$, and $R_4 = 75 \, \Omega$. The equivalent resistance of the circuit, in $\Omega$, is:

Resistances of $6\, \Omega$ each are connected in the manner shown in the adjoining figure. With the current $0.5\, A$ as shown in the figure, the potential difference $V_P - V_Q$ is .............. $V$.

In the circuit shown,the capacitance of the capacitor is $2\,\mu F$. Find the current flowing through the $2\,\Omega$ resistor in $A$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module