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(A) The unit of the rate constant $K$ for a reaction of order $n$ is given by the formula: $(mol \ L^{-1})^{1-n} \ s^{-1}$.Given the unit is $L^2 \ mo

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$3$

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(A) The unit of the rate constant $K$ for a reaction of order $n$ is given by the formula: $(mol \ L^{-1})^{1-n} \ s^{-1}$.Given the unit is $L^2 \ mol^{-2} \ s^{-1}$,which can be rewritten as $mol^{-2} \ L^2 \ s^{-1}$.Comparing this with $(mol \ L^{-1})^{1-n} \ s^{-1}$,we have:$(mol \ L^{-1})^{1-n} = mol^{-2} \ L^2$.This implies $1-n = -2$.Solving for $n$,we get $n = 1 + 2 = 3$.Therefore,the order of the reaction is $3$.

For a certain reaction,the rate constant $K = 2.37 \times 10^2 \ L^2 \ mol^{-2} \ s^{-1}$. What is the order of the reaction?

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