(C) The rate law for the reaction is given by $r = k[A]^m$,where $m$ is the order of the reaction with respect to $A$. According to the problem,when t

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(C) The rate law for the reaction is given by $r = k[A]^m$,where $m$ is the order of the reaction with respect to $A$. According to the problem,when the concentration of $A$ is increased four times,the rate becomes $2r$. So,$2r = k[4A]^m$. Dividing the second equation by the first: $\frac{2r}{r} = \frac{k[4A]^m}{k[A]^m}$. $2 = 4^m$. Taking the logarithm or expressing $4$ as $2^2$: $2^1 = (2^2)^m = 2^{2m}$. Equating the exponents: $1 = 2m$,which gives $m = 0.5$.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

Medium

For a chemical reaction $A \to B$,it is found that the rate of reaction doubles when the concentration of $A$ is increased four times. The order of the reaction with respect to $A$ is:

AIIMS 1997 All AIIMS

A
$2$
B
$1$
C
$0.5$
D
$0$

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Class 12

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Chemical Kinetics

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Rate law , Rate constant , Order of Reaction and Molecularity

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AIIMS 1997 Paper All AIIMS years →

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For a chemical reaction $A \to B$,it is found that the rate of reaction doubles when the concentration of $A$ is increased four times. The order of the reaction with respect to $A$ is:

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