For a common-emitter amplifier, the voltage gain is $40$. Its input and output impedances are $100 \ \Omega$ and $400 \ \Omega$, respectively. The power gain of the $CE$ amplifier will be

In a $CE$ transistor,when the base current increases by $60 \mu A$,the change in base-emitter voltage is $1.2 \ V$. Then the input resistance is: (in $\Omega$)

In the following transistor amplifier circuit,$\beta = 50$. The $V_{CE}$ of the transistor is .......... $V$.

$A$ transistor has a voltage gain '$A$'. If a fraction '$\beta$' of its output is fed back to the input of the transistor,then the transistor becomes an oscillator when:

Three terminals of a transistor,denoted by $P, Q,$ and $R,$ are tested using a multimeter. No conduction occurs between $P$ and $Q.$ When the negative lead of the multimeter is connected to $R$ and the positive lead is connected to either $P$ or $Q,$ the meter shows some resistance. Which of the following options is correct for the given transistor?

In the circuit shown in the figure,when the input voltage $V_i$ is $10\, V$,$V_{BE}$ is zero and $V_{CE}$ is also zero. Find the values of $I_B$,$I_C$,and $\beta$.