For a gas frac{R}{C_v} = 0.4,where R is the u | vedclass

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(A) We are given the ratio $\frac{R}{C_v} = 0.4$. Using the Mayer's relation $R = C_p - C_v$,we can substitute $R$ in the given expression: $\frac{C_p

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rigid diatomic

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(A) We are given the ratio $\frac{R}{C_v} = 0.4$. Using the Mayer's relation $R = C_p - C_v$,we can substitute $R$ in the given expression: $\frac{C_p - C_v}{C_v} = 0.4$ $\frac{C_p}{C_v} - 1 = 0.4$ $\frac{C_p}{C_v} = 1.4$ Since the adiabatic index $\gamma = \frac{C_p}{C_v}$,we have $\gamma = 1.4$. For a gas,$\gamma = 1 + \frac{2}{f}$,where $f$ is the degree of freedom. $1.4 = 1 + \frac{2}{f} \Rightarrow 0.4 = \frac{2}{f} \Rightarrow f = \frac{2}{0.4} = 5$. $A$ gas with $5$ degrees of freedom corresponds to a rigid diatomic molecule ($3$ translational + $2$ rotational degrees of freedom).

For a gas $\frac{R}{C_v} = 0.4$,where $R$ is the universal gas constant and $C_v$ is the molar specific heat at constant volume. The gas is made up of molecules which are

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