(C) The Freundlich adsorption isotherm is given by $\frac{x}{m} = k p^{1/n}$.Taking the logarithm on both sides,we get $\log \frac{x}{m} = \log k + \f

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$\log \frac{x}{m}$ vs $\log p$ is a straight line with slope equal to $0.2$

(C) The Freundlich adsorption isotherm is given by $\frac{x}{m} = k p^{1/n}$.Taking the logarithm on both sides,we get $\log \frac{x}{m} = \log k + \frac{1}{n} \log p$.This equation represents a straight line of the form $y = mx + c$,where the slope is $\frac{1}{n}$.Given $n = 5$,the slope is $\frac{1}{5} = 0.2$.

Class 12 Chemistry Surface Chemistry Adsorption and Adsorption isotherm

Medium

For a gas-solid adsorbent system,the adsorption isotherm $\frac{x}{m}=k p^{1/n}$ is applicable,where $n=5$ in the specified case. Point out the correct statement:

AIIMS 2019 All AIIMS

A
$\frac{x}{m}$ vs $p$ plot is a linear graph with slope equal to $5$
B
$\log \frac{x}{m}$ vs $\log p$ plot is a straight line with slope equal to $5$
C
$\log \frac{x}{m}$ vs $\log p$ is a straight line with slope equal to $0.2$
D
none of these