For a given chemical reaction $A \rightarrow B$ at $300 \ K$,the free energy change is $-49.4 \ kJ \ mol^{-1}$ and the enthalpy of reaction is $51.4 \ kJ \ mol^{-1}$. The entropy change of the reaction is $..... \ J \ K^{-1} \ mol^{-1}$.

  • A
    $336$
  • B
    $390$
  • C
    $460$
  • D
    $551$

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Similar Questions

The effect of temperature on the spontaneity of reactions is represented as follows:
ConditionDetails
$A$. $\Delta H: +, \Delta S: -$$T$: any $T$, Spontaneity: Non-spontaneous
$B$. $\Delta H: +, \Delta S: +$$T$: low $T$, Spontaneity: Non-spontaneous
$C$. $\Delta H: -, \Delta S: -$$T$: low $T$, Spontaneity: Spontaneous
$D$. $\Delta H: -, \Delta S: +$$T$: any $T$, Spontaneity: Spontaneous

Which of the above conditions are correctly matched?

The signs of $\Delta_r H^{\circ}$ and $\Delta_r S^{\circ}$ for a reaction to be spontaneous at all temperatures respectively are

For the reaction $A \longrightarrow B$,$\Delta H^{\circ} = 7.5 \, kJ \, mol^{-1}$ and $\Delta S^{\circ} = 25 \, J \, K^{-1} \, mol^{-1}$. The value of $\Delta G^{\circ}$ and the temperature at which the reaction reaches equilibrium are,respectively:

For the decomposition reaction of $N_2O_4$,$\Delta H = 58.04 \, kJ$ and $\Delta S = 176.7 \, J/K$. Calculate $\Delta G$ in $kJ$ at $T = 298 \, K$.

$A$ reaction,$A + B \rightarrow C + D + q$,is found to have a positive entropy change. The reaction will be:

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