(C) The formula for the mean using the step-deviation method is given by:$\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \right) \times

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(C) The formula for the mean using the step-deviation method is given by:$\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \right) \times c$Given values:$A = 62.5$,$\Sigma f_{i} u_{i} = -13$,$\Sigma f_{i} = 100$,$c = 15$Substituting these values into the formula:$\bar{x} = 62.5 + \left( \frac{-13}{100} \right) \times 15$$\bar{x} = 62.5 + (-0.13) \times 15$$\bar{x} = 62.5 - 1.95$$\bar{x} = 60.55$

Class 10 Mathematics Statistics Mean of Grouped Data

Easy

For a given frequency distribution,$\Sigma f_{i} u_{i} = -13$,$n = \Sigma f_{i} = 100$,$A = 62.5$ and $c = 15$. Then,mean $\bar{x} = \dots$

A
$61.5$
B
$64.45$
C
$60.55$
D
$61.2$

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Statistics

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Mean of Grouped Data

The class length of the excluding type of class $20-30$ in a frequency distribution is .......

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The daily income of a sample of $50$ employees is tabulated as follows:

Income (in $Rs.$) $1-200$ $201-400$ $401-600$ $601-800$

Number of employees $14$ $15$ $14$ $7$

Find the mean daily income of the employees. (in $.5$)

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$\Sigma(x_{i} - \bar{x}) = \ldots \ldots \ldots$

Easy

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For a given frequency distribution,$\bar{x}=54.3, \Sigma f_{i} u_{i}=2, n=25$ and $c=10$. Then the assumed mean $A = \dots$

Medium

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Consider the following distribution:
Marks obtained Number of students
More than or equal to $0$ $63$
More than or equal to $10$ $58$
More than or equal to $20$ $55$
More than or equal to $30$ $51$
More than or equal to $40$ $48$
More than or equal to $50$ $42$

The frequency of the class $30-40$ is:

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Income (in $Rs.$)	$1-200$	$201-400$	$401-600$	$601-800$
Number of employees	$14$	$15$	$14$	$7$

Marks obtained	Number of students
More than or equal to $0$	$63$
More than or equal to $10$	$58$
More than or equal to $20$	$55$
More than or equal to $30$	$51$
More than or equal to $40$	$48$
More than or equal to $50$	$42$

For a given frequency distribution,$\Sigma f_{i} u_{i} = -13$,$n = \Sigma f_{i} = 100$,$A = 62.5$ and $c = 15$. Then,mean $\bar{x} = \dots$

Similar Questions

The class length of the excluding type of class $20-30$ in a frequency distribution is .......

The daily income of a sample of $50$ employees is tabulated as follows: Income (in $Rs.$) $1-200$ $201-400$ $401-600$ $601-800$ Number of employees $14$ $15$ $14$ $7$ Find the mean daily income of the employees. (in $.5$)

$\Sigma(x_{i} - \bar{x}) = \ldots \ldots \ldots$

For a given frequency distribution,$\bar{x}=54.3, \Sigma f_{i} u_{i}=2, n=25$ and $c=10$. Then the assumed mean $A = \dots$

Consider the following distribution:Marks obtainedNumber of studentsMore than or equal to $0$$63$More than or equal to $10$$58$More than or equal to $20$$55$More than or equal to $30$$51$More than or equal to $40$$48$More than or equal to $50$$42$The frequency of the class $30-40$ is:

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The daily income of a sample of $50$ employees is tabulated as follows:

Income (in $Rs.$) $1-200$ $201-400$ $401-600$ $601-800$

Number of employees $14$ $15$ $14$ $7$

Find the mean daily income of the employees. (in $.5$)