For a normal eye,the least distance of distin | vedclass

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(A) In optometry,the least distance of distinct vision $(LDDV)$ is the closest distance at which an object can be placed so that it can be seen clearl

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(A) In optometry,the least distance of distinct vision $(LDDV)$ is the closest distance at which an object can be placed so that it can be seen clearly by a normal human eye without any strain.For a normal human eye,this distance is standardly defined as $25 \ cm$.To convert this into meters,we divide by $100$:$25 \ cm = 25 / 100 \ m = 0.25 \ m$.Therefore,the correct option is $A$.

For a normal eye,the least distance of distinct vision is......$m$.

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