For a particle in $SHM$,if the amplitude of the displacement is $a$ and the amplitude of velocity is $v$,the amplitude of acceleration is

$A$ particle of mass $0.3 \, kg$ is subjected to a force $F = -kx$ with $k = 15 \, N/m$. What will be its initial acceleration if it is released from a point $20 \, cm$ away from the origin? (in $m/s^2$)

The $x-t$ graph of a particle performing simple harmonic motion is shown in the figure. The acceleration of the particle at $t=2 \ s$ is:

What is the phase difference between the displacement and acceleration of a particle executing $SHM$?

This is the position-time graph of a mass on a spring. What can you say about the velocity and force at the instant indicated by the dashed line? (Positive direction is to the right.)

The acceleration of a particle performing $S.H.M.$ at a distance of $3\;cm$ from the mean position is $12\;cm/s^2$. Its time period is ..... $s$.