For a particle in uniform circular motion,the acceleration $\vec{a}$ at any point $P (R, \theta)$ on the circular path of radius $R$ is (when $\theta$ is measured from the positive $x$-axis and $v$ is uniform speed):

  • A
    $-\frac{v^{2}}{R} \sin \theta \hat{i} + \frac{v^{2}}{R} \cos \theta \hat{j}$
  • B
    $-\frac{v^{2}}{R} \cos \theta \hat{i} + \frac{v^{2}}{R} \sin \theta \hat{j}$
  • C
    $-\frac{v^{2}}{R} \cos \theta \hat{i} - \frac{v^{2}}{R} \sin \theta \hat{j}$
  • D
    $-\frac{v^{2}}{R} \hat{i} + \frac{v^{2}}{R} \hat{j}$

Explore More

Similar Questions

$A$ particle moves with a constant speed $v$ along a circle of radius $R$. What is the change in velocity of the particle as it moves from point $P_1$ to $P_2$?

Difficult
View Solution

$A$ scooter is going round a circular road of radius $100 \,m$ at a speed of $10 \,m/s$. The angular speed of the scooter will be ......... $rad/s$.

What is uniform circular motion? By using a proper figure,derive the equation for centripetal acceleration $a_c = \frac{v^2}{r}$ for uniform circular motion. Show that its direction is towards the center.

Difficult
View Solution

The angular speed of the minute hand of a clock in degrees per second is

The angular velocity of a flywheel making $120$ revolutions per minute is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo