(A) According to Einstein's photoelectric equation, the maximum kinetic energy $(K_{max})$ of the emitted photoelectrons is given by:$K_{max} = \frac{

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(A) According to Einstein's photoelectric equation, the maximum kinetic energy $(K_{max})$ of the emitted photoelectrons is given by:$K_{max} = \frac{hc}{\lambda} - W_0$We know that the stopping potential $V$ is related to the maximum kinetic energy by the equation:$K_{max} = eV$Substituting this into the photoelectric equation:$eV = \frac{hc}{\lambda} - W_0$Rearranging the terms to solve for the wavelength $\lambda$:$\frac{hc}{\lambda} = W_0 + eV$$\lambda = \frac{hc}{W_0 + eV}$

Class 12 Physics Dual Nature of Radiation and Matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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For a photosensitive material, the work function is $W_0$ and the stopping potential is $V$. What is the wavelength of the incident radiation? ($h$ = Planck's constant, $c$ = velocity of light, $e$ = electronic charge)

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A
$\frac{hc}{W_0 + eV}$
B
$\frac{hc}{W_0 - eV}$
C
$hc(W_0 + eV)$
D
$hc(W_0 - eV)$

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Dual Nature of Radiation and Matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

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When a metal is irradiated by monochromatic light,the maximum kinetic energy of the photoelectrons is $1.2 \ eV.$ If the frequency of the light is increased by $50 \%$,then the maximum kinetic energy of the photoelectrons is $3.6 \ eV.$ Evaluate the work function of the metal.

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In the photoelectric emission process from a metal with a work function of $1.8\, eV$,the kinetic energy of the most energetic electrons is $0.5\, eV$. The corresponding stopping potential is ......... $V$.

MediumAIPMT 2011

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For a photosensitive material, the work function is $W_0$ and the stopping potential is $V$. What is the wavelength of the incident radiation? ($h$ = Planck's constant, $c$ = velocity of light, $e$ = electronic charge)

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The work function of Cesium is $2.27 eV$. The cut-off voltage which stops the emission of electrons from a cesium cathode irradiated with light of $600 nm$ wavelength is

The work function of a metallic surface is $5.01 \, eV$. The photo-electrons are emitted when light of wavelength $2000 \, \mathring{A}$ falls on it. The potential difference applied to stop the fastest photo-electrons is ............... $volt$ $[h = 4.14 \times 10^{-15} \, eV \cdot s]$

All electrons ejected from a metallic surface by incident light of wavelength $400 \,nm$ travelled $1 \,m$ in the direction of a uniform electric field of $2 \,N/C$ and came to rest. The work function of the surface is (in $\,eV$)

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