Medium
For a reaction $H_2 + I_2 \rightleftharpoons 2HI$ at $721 \ K$,the value of equilibrium constant is $50$. If $0.5 \ mol$ each of $H_2$ and $I_2$ is added to the system,the value of equilibrium constant will be
- A$40$
- B$60$
- C$50$
- D$30$
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