(B) For a general reaction $aA \rightarrow bB$,the rate of reaction is given by: Rate $= -\frac{1}{a} \frac{d[A]}{dt} = \frac{1}{b} \frac{d[B]}{dt}$ G

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$-\frac{d[A]}{dt} = \frac{1}{4} \frac{d[B]}{dt}$

(B) For a general reaction $aA \rightarrow bB$,the rate of reaction is given by: Rate $= -\frac{1}{a} \frac{d[A]}{dt} = \frac{1}{b} \frac{d[B]}{dt}$ Given the reaction $\frac{1}{2} A \rightarrow 2B$,we have $a = \frac{1}{2}$ and $b = 2$. Substituting these values into the rate expression: $-\frac{1}{1/2} \frac{d[A]}{dt} = \frac{1}{2} \frac{d[B]}{dt}$ $-2 \frac{d[A]}{dt} = \frac{1}{2} \frac{d[B]}{dt}$ Dividing both sides by $2$: $-\frac{d[A]}{dt} = \frac{1}{4} \frac{d[B]}{dt}$

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

For a reaction $\frac{1}{2} A \rightarrow 2B,$ the rate of disappearance of $A$ is related to the rate of appearance of $B$ by the expression:

AIEEE 2008 All AIEEE

A
$-\frac{d[A]}{dt} = \frac{1}{2} \frac{d[B]}{dt}$
B
$-\frac{d[A]}{dt} = \frac{1}{4} \frac{d[B]}{dt}$
C
$-\frac{d[A]}{dt} = \frac{d[B]}{dt}$
D
$-\frac{d[A]}{dt} = 4 \frac{d[B]}{dt}$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Data Entry - Chemistry

Subtopic

Level 0 of all question bank

Previous Year

AIEEE 2008 Paper All AIEEE years →

Charges of $+\frac{10}{3} \times 10^{-9} \text{ C}$ are placed at each of the four corners of a square of side $8 \text{ cm}$. The potential at the intersection of the diagonals is:

View Solution

The Vernier scale of a travelling microscope has $50$ divisions which coincide with $49$ main scale divisions. If each main scale division is $0.5 \text{ mm}$,then the least count of the microscope is

KCET 2022

View Solution

$A$ large open tank has two holes in the wall. One is a square hole of side $L$ at a depth $y$ from the top and the other is a circular hole of radius $R$ at a depth $4y$ from the top. When the tank is completely filled with water,the quantities of water flowing out per second from the two holes are the same. Then the value of $R$ is

AP EAMCET 2011

View Solution

If $f(x) = x^5 - 5x^4 + 5x^3 - 10$ has local maximum and minimum at $x = p$ and $x = q$,respectively,then $(p, q)$ equals

View Solution

If $\cos 2x = (\sqrt{2} + 1) \left(\cos x - \frac{1}{\sqrt{2}}\right)$ and $\cos x \neq \frac{1}{\sqrt{2}}$,then $x \in$

TS EAMCET 2005

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

For a reaction $\frac{1}{2} A \rightarrow 2B,$ the rate of disappearance of $A$ is related to the rate of appearance of $B$ by the expression:

Similar Questions

Charges of $+\frac{10}{3} \times 10^{-9} \text{ C}$ are placed at each of the four corners of a square of side $8 \text{ cm}$. The potential at the intersection of the diagonals is:

The Vernier scale of a travelling microscope has $50$ divisions which coincide with $49$ main scale divisions. If each main scale division is $0.5 \text{ mm}$,then the least count of the microscope is

If $f(x) = x^5 - 5x^4 + 5x^3 - 10$ has local maximum and minimum at $x = p$ and $x = q$,respectively,then $(p, q)$ equals

If $\cos 2x = (\sqrt{2} + 1) \left(\cos x - \frac{1}{\sqrt{2}}\right)$ and $\cos x \neq \frac{1}{\sqrt{2}}$,then $x \in$

Vedclass Test Series

Exam Paper Generator

Online Exam Module