For a satellite,the escape velocity is $11 \ km/s$. If the satellite is launched at an angle of $60^\circ$ with the vertical,then the escape velocity will be ........... $km/s$.
- A$11$
- B$11\sqrt{3}$
- C$\frac{11}{\sqrt{3}}$
- D$33$
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Similar Questions
Earth has mass $8$ times and radius $2$ times that of a planet. If the escape velocity from the Earth is $11.2 \ km/s$,the escape velocity in $km/s$ from the planet will be:
The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. If the escape velocity from the earth is $V_{e}$,then the escape velocity from the planet is:
Escape velocity at the surface of the Earth is $11.2 \, km/s$. If the radius of a planet is double that of the Earth but its mean density is the same as that of the Earth,then the escape velocity will be ........ $km/s$.
Difficult
View SolutionEscape velocity on Earth is $11.2 \, km/s$. What would be the escape velocity on a planet whose mass is $1000$ times and radius is $10$ times that of Earth?
Medium
View SolutionTwo planets $P_1$ and $P_2$ with equal mass have radii $R_1$ and $R_2$, respectively, where $R_2 = \frac{R_1}{2}$. The escape speeds of $P_1$ and $P_2$ are $v_1$ and $v_2$, respectively. Then $\frac{v_2}{v_1}$ is :
MediumNEET 2026
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