For a small angled prism with prism angle $A$,the angle of minimum deviation $\delta$ varies with the refractive index $\mu$ of the prism as shown in the graph.

Light rays from a source are incident on a glass prism of refractive index $\mu$ and prism angle $\alpha$. At near-normal incidence,the angle of deviation of the emerging rays is:

The ratio of the angle of minimum deviation of a prism in air to that when it is dipped in water is (given $_a\mu_g = 3/2$ and $_a\mu_w = 4/3$).

$A$ ray of light is incident at an angle of incidence '$i$' on one surface of a prism of small angle '$A$' and emerges normally from the other surface. If the refractive index of the material of the prism is '$\mu$',then the angle of incidence is equal to

Consider the following statements for the refraction of light through a prism,when the angle of deviation is minimum.
$(A)$ The refracted ray inside the prism becomes parallel to the base.
$(B)$ Larger angle prisms provide smaller angle of minimum deviation.
$(C)$ The angle of incidence and the angle of emergence become equal.
$(D)$ There are always two sets of angles of incidence for which the deviation will be the same,except at the minimum deviation setting.
$(E)$ The angle of refraction becomes double the prism angle.
Choose the correct answer from the options given below.

$A$ ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence,and each of these angles is equal to $\left(\frac{3}{4}\right)^{th}$ of the angle of the prism. The angle of deviation is: (in $^{\circ}$)