For a small angled prism with prism angle $A$,the angle of minimum deviation $(\delta_m)$ varies with the refractive index $(\mu)$ of the prism as shown in the graph.

An equilateral prism $P$ produces a minimum deviation for a given light ray. Additional prisms $Q$ and $R$ of the same shape and material are placed as shown in the figure. The ray will experience:

Two equilateral-triangular prisms $P_1$ and $P_2$ are kept with their sides parallel to each other,in vacuum,as shown in the figure. $A$ light ray enters prism $P_1$ at an angle of incidence $\theta$ such that the outgoing ray undergoes minimum deviation in prism $P_2$. If the respective refractive indices of $P_1$ and $P_2$ are $\sqrt{\frac{3}{2}}$ and $\sqrt{3}$,then $\theta = \sin^{-1}\left[\sqrt{\frac{3}{2}} \sin \left(\frac{\pi}{\beta}\right)\right]$,where the value of $\beta$ is:

Three prisms $1, 2,$ and $3$ have a prism angle $A = 60^{\circ}$. Their refractive indices are $1.4, 1.5,$ and $1.6$ respectively. If $\delta_1, \delta_2,$ and $\delta_3$ are their angles of deviation,then:

Monochromatic light is incident on a glass prism of angle $A$. If the refractive index of the material of the prism is $\mu$,a ray,incident at an angle $\theta$ on the face $AB$,would get transmitted through the face $AC$ of the prism provided:

The refractive index of a prism with apex angle $A$ is $\cot(A/2)$. The angle of minimum deviation is: