For a symmetric (equilateral) prism,the prism | vedclass

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(A) The general prism formula is given by $\mu = \frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin \left(\frac{A}{2}\right)}$.For a symmetric (equila

Vedclass · Accepted Answer

$2 \sin \left(30^{\circ}+\frac{\delta_m}{2}\right)$

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(A) The general prism formula is given by $\mu = \frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin \left(\frac{A}{2}\right)}$.For a symmetric (equilateral) prism,the prism angle $A = 60^{\circ}$.Substituting $A = 60^{\circ}$ into the formula:$\mu = \frac{\sin \left(\frac{60^{\circ}+\delta_m}{2}\right)}{\sin \left(\frac{60^{\circ}}{2}\right)}$$\mu = \frac{\sin \left(30^{\circ}+\frac{\delta_m}{2}\right)}{\sin 30^{\circ}}$Since $\sin 30^{\circ} = \frac{1}{2}$,we have:$\mu = \frac{\sin \left(30^{\circ}+\frac{\delta_m}{2}\right)}{1/2}$$\mu = 2 \sin \left(30^{\circ}+\frac{\delta_m}{2}\right)$.

For a symmetric (equilateral) prism,the prism formula can be written as

Similar Questions

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