For a transistor,current gain (beta) = 50. To | vedclass

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(D) The current gain $(\beta)$ of a transistor is defined as the ratio of the change in collector current $(\Delta I_C)$ to the change in base current

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$(\frac{350}{50}) \mu A$

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(D) The current gain $(\beta)$ of a transistor is defined as the ratio of the change in collector current $(\Delta I_C)$ to the change in base current $(\Delta I_B)$.$\beta = \frac{\Delta I_C}{\Delta I_B}$Given that $\beta = 50$ and the change in collector current $\Delta I_C = 350 \mu A$.Rearranging the formula to solve for the change in base current $(\Delta I_B)$:$\Delta I_B = \frac{\Delta I_C}{\beta}$Substituting the given values:$\Delta I_B = \frac{350 \mu A}{50} = 7 \mu A$.Thus,the base current should be changed by $(\frac{350}{50}) \mu A$.

For a transistor,current gain $(\beta) = 50$. To change the collector current by $350 \mu A$,the base current should be changed by:

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