For a triode,at {V_g} = -1 text{ V},the follo | vedclass

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(C) The plate resistance ${r_p}$ of a triode is defined as the ratio of the change in plate voltage to the change in plate current at a constant grid

Vedclass · Accepted Answer

$12.5$

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(C) The plate resistance ${r_p}$ of a triode is defined as the ratio of the change in plate voltage to the change in plate current at a constant grid voltage.${r_p} = \left( \frac{\Delta V_p}{\Delta I_p} ight)_{V_g = 	ext{constant}}$Given:${V_{p1}} = 75 	ext{ V}, {I_{p1}} = 2 	ext{ mA} = 2 	imes 10^{-3} 	ext{ A}$${V_{p2}} = 100 	ext{ V}, {I_{p2}} = 4 	ext{ mA} = 4 	imes 10^{-3} 	ext{ A}$Calculating the change:$\Delta V_p = 100 - 75 = 25 	ext{ V}$$\Delta I_p = (4 - 2) 	ext{ mA} = 2 	ext{ mA} = 2 	imes 10^{-3} 	ext{ A}$Substituting the values:${r_p} = \frac{25}{2 	imes 10^{-3}} = 12.5 	imes 10^3 \Omega = 12.5 	ext{ k}\Omega$.

$V_g$ (volt)	$0$	$-2$	$-4$	$-6$
$I_p$ (mA) for $V_p = 150$ $V$	$15$	$12.5$	$10$	$7.5$
$I_p$ (mA) for $V_p = 120$ $V$	$10$	$7.5$	$5$	$2.5$

For a triode,at ${V_g} = -1 \text{ V}$,the following observations were taken: ${V_p} = 75 \text{ V}, {I_p} = 2 \text{ mA}$ and ${V_p} = 100 \text{ V}, {I_p} = 4 \text{ mA}$. The value of plate resistance will be ...... $k\Omega$.

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