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(A) For a uniformly charged thin spherical shell of radius $R$ and charge $Q$:$1$. Inside the shell $(r < R)$,the electric field is zero,which implies

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(A) For a uniformly charged thin spherical shell of radius $R$ and charge $Q$:$1$. Inside the shell $(r $2$. Outside the shell $(r \ge R)$,the shell behaves like a point charge placed at its center,so the potential follows the inverse relation $V_{	ext{outside}} = \frac{kQ}{r}$,where $r$ is the distance from the center.$3$. Thus,the graph of $V$ versus $r$ is a horizontal line for $r \le R$ and a rectangular hyperbola for $r > R$.

For a uniformly charged thin spherical shell,the electric potential $(V)$ radially away from the center $(O)$ of the shell can be graphically represented as:

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