For a wire,$\frac{R}{l} = \frac{1}{2} \, \Omega/cm$ and the length of the wire is $l = 5 \, cm$. If a potential difference of $1 \, V$ is applied across it,the current through the wire will be: $(R = \text{Resistance})$ (in $A$)
- A$0.4$
- B$4$
- C$25$
- D$2.5$
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