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(B) In an astronomical telescope,the objective lens forms an image of a distant object at its focal plane. For normal adjustment,the final image is fo

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$L \geq f_{0}+f_{e}$

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(B) In an astronomical telescope,the objective lens forms an image of a distant object at its focal plane. For normal adjustment,the final image is formed at infinity,and the distance between the objective lens and the eyepiece is $L = f_{0} + f_{e}$. When the final image is formed at the near point (least distance of distinct vision),the eyepiece is moved closer to the objective lens,but the total length $L$ must be at least $f_{0} + f_{e}$ to accommodate the focal lengths of both lenses in the optical path. Therefore,the tube length $L$ is generally given by $L \geq f_{0} + f_{e}$.

For an astronomical telescope,the focal length of the objective lens is $f_{0}$ and the eyepiece lens is $f_{e}$. Then the tube length of the telescope is . . . . . . .

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