For an isothermal expansion of a perfect gas, | vedclass

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(B) For an isothermal process,the temperature $T$ remains constant.According to the ideal gas equation,$PV = nRT$.Since $n$,$R$,and $T$ are constant,$

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$-\frac{\Delta V}{V}$

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(B) For an isothermal process,the temperature $T$ remains constant.According to the ideal gas equation,$PV = nRT$.Since $n$,$R$,and $T$ are constant,$PV = 	ext{constant}$.Differentiating both sides with respect to $V$,we get:$P \Delta V + V \Delta P = 0$Rearranging the terms,we get $V \Delta P = -P \Delta V$.Dividing both sides by $PV$,we obtain:$\frac{\Delta P}{P} = -\frac{\Delta V}{V}$.

For an isothermal expansion of a perfect gas,the value of $\frac{\Delta P}{P}$ is equal to:

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