For an octahedral complex,which of the follow | vedclass

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Question

(A) The Crystal Field Stabilization Energy $(CFSE)$ for an octahedral complex is calculated as $CFSE = [n(t_{2g}) 	imes (-0.4 \Delta_{o}) + n(e_{g})

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Low spin $d^{5}$

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(A) The Crystal Field Stabilization Energy $(CFSE)$ for an octahedral complex is calculated as $CFSE = [n(t_{2g}) 	imes (-0.4 \Delta_{o}) + n(e_{g}) 	imes (0.6 \Delta_{o})]$.For Low spin $d^{5}$: $t_{2g}^{5} e_{g}^{0}$,$CFSE = 5(-0.4 \Delta_{o}) + 0(0.6 \Delta_{o}) = -2.0 \Delta_{o}$.For Low spin $d^{4}$: $t_{2g}^{4} e_{g}^{0}$,$CFSE = 4(-0.4 \Delta_{o}) + 0(0.6 \Delta_{o}) = -1.6 \Delta_{o}$.For High spin $d^{7}$: $t_{2g}^{5} e_{g}^{2}$,$CFSE = 5(-0.4 \Delta_{o}) + 2(0.6 \Delta_{o}) = -2.0 + 1.2 = -0.8 \Delta_{o}$.For High spin $d^{6}$: $t_{2g}^{4} e_{g}^{2}$,$CFSE = 4(-0.4 \Delta_{o}) + 2(0.6 \Delta_{o}) = -1.6 + 1.2 = -0.4 \Delta_{o}$.Comparing the magnitudes,the Low spin $d^{5}$ configuration gives the maximum magnitude of $2.0 \Delta_{o}$.

List-$I$ (Complex)	List-$II$ (Electronic configuration of metal/ion)
$A. [Co(NH_3)_6]^{3+}$	$I. t_{2g}^5 e_g^0$
$B. [CoF_6]^{3-}$	$II. t_{2g}^6 e_g^0$
$C. [Ni(CO)_4]$	$III. t_{2g}^4 e_g^2$
$D. [Fe(CN)_6]^{3-}$	$IV. t^4 e^6$

For an octahedral complex,which of the following $d-$electronic configuration will give the maximum magnitude of crystal field stabilization energy,in terms of $\Delta_{o}$?

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Among the following pairs of complexes,in which case is the $\Delta_0$ value higher for the first one?

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$III$- $[Fe(H_2O)_6]^{3+}$
$IV$- $[Fe(CN)_6]^{3+}$

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