For any A.P.,T_{30} - T_{20} = ldots ldots ld | vedclass

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(B) The $n^{th}$ term of an $A.P.$ is given by $T_n = a + (n - 1)d$,where $a$ is the first term and $d$ is the common difference.For $T_{30}$,we have

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$10d$

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(B) The $n^{th}$ term of an $A.P.$ is given by $T_n = a + (n - 1)d$,where $a$ is the first term and $d$ is the common difference.For $T_{30}$,we have $T_{30} = a + (30 - 1)d = a + 29d$.For $T_{20}$,we have $T_{20} = a + (20 - 1)d = a + 19d$.Now,calculating the difference: $T_{30} - T_{20} = (a + 29d) - (a + 19d)$.$T_{30} - T_{20} = a - a + 29d - 19d$.$T_{30} - T_{20} = 10d$.

For any $A.P.$,$T_{30} - T_{20} = \ldots \ldots \ldots \ldots$

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