For the given system,find the value of theta_ | vedclass

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(D) Consider the equilibrium of block $B$ (mass $m$): Horizontal force: $T_1 \sin 	heta_1 = mg$ Vertical force: $T_1 \cos 	heta_1 = mg$ Dividing the

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$	an^{-1}\left(\frac{1}{2}ight)$

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(D) Consider the equilibrium of block $B$ (mass $m$): Horizontal force: $T_1 \sin 	heta_1 = mg$ Vertical force: $T_1 \cos 	heta_1 = mg$ Dividing these,$	an 	heta_1 = 1 \Rightarrow 	heta_1 = 45^o$. Also,$T_1 = \sqrt{(mg)^2 + (mg)^2} = \sqrt{2}mg$. Now,consider the equilibrium of the system containing both blocks $A$ and $B$ (total mass $2m$): Horizontal force: $T_2 \sin 	heta_2 = mg$ (only the horizontal force $mg$ acts on block $B$) Vertical force: $T_2 \cos 	heta_2 = 2mg$ (total weight of $A$ and $B$) Dividing the horizontal force by the vertical force: $\frac{T_2 \sin 	heta_2}{T_2 \cos 	heta_2} = \frac{mg}{2mg}$ $	an 	heta_2 = \frac{1}{2}$ $	herefore 	heta_2 = 	an^{-1}\left(\frac{1}{2}ight)$.

For the given system,find the value of $\theta_2$.

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