For a sodium atom,the number of electrons wit | vedclass

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Question

(B) The electronic configuration of a sodium atom $(Z = 11)$ is $1s^2 2s^2 2p^6 3s^1$.For $m = 0$,the electrons must be in $s$-orbitals or $p_z$-orbit

Vedclass · Accepted Answer

$7$

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(B) The electronic configuration of a sodium atom $(Z = 11)$ is $1s^2 2s^2 2p^6 3s^1$.For $m = 0$,the electrons must be in $s$-orbitals or $p_z$-orbitals.In $1s^2$,there are $2$ electrons with $m = 0$.In $2s^2$,there are $2$ electrons with $m = 0$.In $2p^6$,the orbitals are $2p_x, 2p_y, 2p_z$. The $2p_z$ orbital has $m = 0$ and contains $2$ electrons.In $3s^1$,there is $1$ electron with $m = 0$.Total number of electrons with $m = 0$ is $2 + 2 + 2 + 1 = 7$.

For a sodium atom,the number of electrons with $m = 0$ will be:

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