For some given data,if $Z = 95$ and $\bar{x} = 98,$ then $M = \ldots \ldots \ldots$

Consider the following frequency distribution of the heights of $60$ students of a class:

Height (in $cm$)	Number of students
$150-155$	$15$
$155-160$	$13$
$160-165$	$10$
$165-170$	$8$
$170-175$	$9$
$175-180$	$5$

The sum of the lower limit of the modal class and upper limit of the median class is:

$Z - M = \ldots \ldots \ldots \times (M - \bar{x})$

If $3 \bar{x} = 2 M = 60,$ then $Z = \dots$

The following data gives the distribution of total monthly household expenditure of $200$ families of a village. Find the modal monthly expenditure of the families. Also,find the mean monthly expenditure:
$\begin{array}{|c|c|} \hline \text{Expenditure (in Rs)} & \text{Number of families} \\ \hline 1000-1500 & 24 \\ 1500-2000 & 40 \\ 2000-2500 & 33 \\ 2500-3000 & 28 \\ 3000-3500 & 30 \\ 3500-4000 & 22 \\ 4000-4500 & 16 \\ 4500-5000 & 7 \\ \hline \end{array}$

Consider the data:

Class	$65-85$	$85-105$	$105-125$	$125-145$	$145-165$	$165-185$	$185-205$
Frequency	$4$	$5$	$13$	$20$	$14$	$7$	$4$

The difference between the upper limit of the median class and the lower limit of the modal class is: