For spontaneous polymerization, which of the | vedclass

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(A, B, D) For a process to be spontaneous, the Gibbs free energy change, $\Delta G$, must be negative. Polymerization involves the association of mono

Vedclass · Accepted Answer

$\Delta S$ is negative

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(A, B, D) For a process to be spontaneous, the Gibbs free energy change, $\Delta G$, must be negative. Polymerization involves the association of monomer units into a long chain, which leads to a decrease in the randomness of the system, meaning $\Delta S$ is negative. According to the Gibbs-Helmholtz equation, $\Delta G = \Delta H - T\Delta S$. Since $\Delta G < 0$ and $\Delta S < 0$, for the process to be spontaneous, $\Delta H$ must be negative and its magnitude must be greater than $T\Delta S$.

For spontaneous polymerization, which of the following is (are) correct?

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