For the A.P. 3, 13, 23, 33, ldots, its ldots | vedclass

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(D) Given the Arithmetic Progression $(A.P.)$ is $3, 13, 23, 33, \ldots$Here,the first term $a = 3$ and the common difference $d = 13 - 3 = 10$.We nee

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$22$

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(D) Given the Arithmetic Progression $(A.P.)$ is $3, 13, 23, 33, \ldots$Here,the first term $a = 3$ and the common difference $d = 13 - 3 = 10$.We need to find the term $n$ such that $T_n = T_{21} + 10$.The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n - 1)d$.Substituting the values,we get $a + (n - 1)d = (a + 20d) + 10$.Since $d = 10$,we have $a + (n - 1)10 = a + 20(10) + 10$.Subtracting $a$ from both sides: $(n - 1)10 = 200 + 10$.$(n - 1)10 = 210$.Dividing by $10$,we get $n - 1 = 21$.Therefore,$n = 22$.

For the $A.P.$ $3, 13, 23, 33, \ldots,$ its $\ldots \ldots \ldots \ldots$ term exceeds its $21^{st}$ term by $10.$

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