For the alkyne with formula C_6H_{10},the num | vedclass

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(C) An alkyne has acidic hydrogen if it is a terminal alkyne (triple bond at the end of the chain,$R-C \equiv CH$).For the formula $C_6H_{10}$,the pos

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$4, 3$

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(C) An alkyne has acidic hydrogen if it is a terminal alkyne (triple bond at the end of the chain,$R-C \equiv CH$).For the formula $C_6H_{10}$,the possible isomers are:$1$. $Hex-1-yne$ $(CH_3CH_2CH_2CH_2C \equiv CH)$ - Terminal (Acidic)$2$. $3-Methylpent-1-yne$ $(CH_3CH_2CH(CH_3)C \equiv CH)$ - Terminal (Acidic)$3$. $4-Methylpent-1-yne$ $(CH_3CH(CH_3)CH_2C \equiv CH)$ - Terminal (Acidic)$4$. $3,3-Dimethylbut-1-yne$ $((CH_3)_3CC \equiv CH)$ - Terminal (Acidic)These $4$ isomers are terminal alkynes,so $x = 4$.Non-terminal (internal) alkynes have no acidic hydrogens:$1$. $Hex-2-yne$ $(CH_3CH_2CH_2C \equiv CCH_3)$$2$. $Hex-3-yne$ $(CH_3CH_2C \equiv CCH_2CH_3)$$3$. $4-Methylpent-2-yne$ $(CH_3CH(CH_3)C \equiv CCH_3)$These $3$ isomers are internal alkynes,so $y = 3$.Thus,$x = 4$ and $y = 3$.

For the alkyne with formula $C_6H_{10}$,the number of alkynes with acidic hydrogens is $x$ and the number of alkynes with no acidic hydrogens is $y$. $x$ and $y$ are respectively:

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