For the circuit shown below,calculate the val | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The total voltage across the series resistor ${R}_{s} = 1000 \, \Omega$ is given by $V_{R} = V_{i} - V_{z} = 100 \, V - 50 \, V = 50 \, V$.The tot

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(D) The total voltage across the series resistor ${R}_{s} = 1000 \, \Omega$ is given by $V_{R} = V_{i} - V_{z} = 100 \, V - 50 \, V = 50 \, V$.The total current flowing through the series resistor is $I = \frac{V_{R}}{R_{s}} = \frac{50 \, V}{1000 \, \Omega} = 0.05 \, A = 50 \, mA$.The current flowing through the load resistor $R = 2000 \, \Omega$ is $I_{L} = \frac{V_{z}}{R} = \frac{50 \, V}{2000 \, \Omega} = 0.025 \, A = 25 \, mA$.Using Kirchhoff's Current Law at the junction,the Zener current $I_{z}$ is $I_{z} = I - I_{L} = 50 \, mA - 25 \, mA = 25 \, mA$.

For the circuit shown below,calculate the value of ${I}_{{z}}$ : (In ${mA}$)

Similar Questions

$A$ reverse biased Zener diode when operated in the breakdown region works as

Which of the following semi-conducting devices is used as a voltage regulator?

The device used for voltage regulation is

In the given circuit,the current through the Zener Diode is close to.......$mA$.

In a Zener diode,

Vedclass Test Series

Exam Paper Generator

Online Exam Module